android regular expression filtering songs

Recently made player, a systematic approach to filter selected music files on the sd card and found that there are a lot of useless files are just some of the audio file, using

 "^ \ \ w + \ \ d {5,} |. \ \ w" 

To filter the song name, but wonder why "b222aa2" This form can also be matched on it? Know how to explain, thank you.<-! Main posts under Banner (D4) -><-! Posts under the main text (D5) ->
Reply:
Were divided into two portions being vertical
The first part ^ \ w + \ d. {5,}
^ \ W + indicates the start by more than one word characters (uppercase and lowercase letters and numbers)
\ D represents a digit
{5} represents an arbitrary character appears at least five times

Part II
\ W a word character

This relationship between the two parts is or is able to match any string of the first portion or the second portion can be matched on a regular
b222aa2 is on how to match it? The second part of the character is clearly not the only one, and it matched
^ \ W + -> b / / at least one word character
\ D -> 2 / / A number
. {5,} -> 22aa2 / / exactly five arbitrary characters


Use on Java regular expression can refer to my translation
http://blog.csdn.net/cugbabybear/article/details/14170355
Reply:
Upstairs positive solution. . .
Reply:

cited a floor CuGBabyBeaR reply:

were vertical lines are divided into two parts
The first part ^ \ w + \ d. {5,}
^ \ W + indicates the start by more than one word characters (uppercase and lowercase letters and numbers)
\ D represents a digit
{5} represents an arbitrary character appears at least five times

Part II
\ W a word character

This relationship between the two parts is or is able to match any string of the first portion or the second portion can be matched on a regular
b222aa2 is on how to match it? The second part of the character is clearly not the only one, and it matched
^ \ W + -> b / / at least one word character
\ D -> 2 / / A number
. {5,} -> 22aa2 / / exactly five arbitrary characters


Use on Java regular expression can refer to my translation
http://blog.csdn.net/cugbabybear/article/details/14170355

Thank you for reply, according to what you said to understand, I looked at the can really match. But I still have doubts ask you next. I started regular is written like this:

 ^ \ \ w + \ \ d {5,} | \ \ w 

The purpose is to filter out the string at the beginning of the English character and containing five or more digits, but found no filtering out the form, 0604a_3907413nGf, BBC0702_243243223snP,
201206cet4. The first two because it contains "_" reasons not to match, but why 201206cet4 failed to match on it? Or do you have a better expression?
Reply:
(? Is) ^ (?! [A-z]). *? \ \ D {5,}. *
Reply:

reference to the third floor azhengye reply:

Thank you for reply, according to what you said to understand, I can really read the next match. But I still have doubts ask you next. I started regular is written like this:

 ^ \ \ w + \ \ d {5,} | \ \ w 

The purpose is to filter out the string at the beginning of the English character and containing five or more digits, but found no filtering out the form, 0604a_3907413nGf, BBC0702_243243223snP,
201206cet4. The first two because it contains "_" reasons not to match, but why 201206cet4 failed to match on it? Or do you have a better expression?

Because metacharacter \ w include alphabetic and numeric characters you can \ w to [a-zA-Z]
Reply:

references, 5th Floor CuGBabyBeaR reply:

because metacharacter \ w include alphabetic and numeric characters you can \ w to [a-zA-Z]

If you talk about that 201206cet4 should be able to match those on the ah.
^ \ \ W -> 2 start, matching
\ \ D {5,} ---> 01206 number just five matches

Can be proved "^ \ \ w + \ \ d {5,} | \ \ w" does not match "201206cet4".
Or is my understanding that because \ \ w + matches directly to the end of the string, and then matching \ \ d {5,} matches when it leads to unsuccessful?
Reply:

reference to the 6th floor azhengye reply:

Quote: references, 5th Floor CuGBabyBeaR reply:

Because metacharacter \ w include alphabetic and numeric characters you can \ w to [a-zA-Z]

If you talk about that 201206cet4 should be able to match those on the ah.
^ \ \ W -> 2 start, matching
\ \ D {5,} ---> 01206 number just five matches

Can be proved "^ \ \ w + \ \ d {5,} | \ \ w" does not match "201206cet4".
Or is my understanding that because \ \ w + matches directly to the end of the string, and then matching \ \ d {5,} matches when it leads to unsuccessful?

What do you use the function?
Reply:

reference to the 7th floor CuGBabyBeaR reply:

What is the function you use?

My code is as follows:

 
music_name = "201206cet4"; 
Pattern pattern = Pattern.compile ("^ \ \ w + \ \ d {5,} | \ \ w"); 
Matcher matcher = pattern.matcher (music_name); 
Judgment matcher.matches () value of false. 

Reply:

reference to the 8th floor azhengye reply:

Quote: references to the 7th floor CuGBabyBeaR reply:

What do you use the function?

My code is as follows:

 
music_name = "201206cet4"; 
Pattern pattern = Pattern.compile ("^ \ \ w + \ \ d {5,} | \ \ w"); 
Matcher matcher = pattern.matcher (music_name); 
Judgment matcher.matches () value of false. 

matches () function is a regular expression string as a whole to determine whether the
201206 can really match regular on but your regular digital so the back end is not matched subtitles
Reply:

reference to the 9th floor CuGBabyBeaR reply:

Quote: references to the 8th floor azhengye reply:

Quote: references to the 7th floor CuGBabyBeaR reply:

What do you use the function?

My code is as follows:

 
music_name = "201206cet4"; 
Pattern pattern = Pattern.compile ("^ \ \ w + \ \ d {5,} | \ \ w"); 
Matcher matcher = pattern.matcher (music_name); 
Judgment matcher.matches () value of false. 

matches () function is a regular expression string as a whole to determine whether the
201206 can really match regular on but your regular rear end is digital so the subtitles do not match

Thank you, you mean the ghost cet engage in, they do not accompany the \ d? Now looks like this error is too obvious. Try again tomorrow, affixed to the end points. Thank you again.