Why editText1 the OnKey event is executed twice Toast? how to avoid

posts by ilove8 edited 2013-10-02 21:49:54

When editText1 nulls Enter, tips can not be empty, but why each prompt is displayed twice, track a bit, the onKey event is executed twice.
The main code is as follows

 
editText1.setOnKeyListener (new View.OnKeyListener () {
@ Override 
public boolean onKey (View arg0, int arg1, KeyEvent arg2) {
boolean bRet = false; 
String s = editText1.getText () toString ();. 
if (arg1 == KeyEvent.KEYCODE_ENTER) {
if (s.length () == 0) {
ShowToast ("can not be empty"); 

bRet = true; 
} 
} 
return bRet; 
} 
}); 

edit1Text text control below there is edit2Text

 
android: layout_width = "match_parent" 
android: layout_height = "wrap_content"> 

android: id = "@ + id/editText1" 
android: layout_width = "0dip" 
android: layout_height = "wrap_content" 
android: layout_weight = "1" 
android: singleLine = "true" 
android: ems = "10"> 

 
 

 

android: layout_width = "match_parent" 
android: layout_height = "wrap_content"> 

android: id = "@ + id/editText2" 
android: layout_width = "0dip" 
android: layout_height = "wrap_content" 
android: layout_weight = "1" 
android: singleLine = "true" 
android: ems = "10" /> 

 

Two tips on how to avoid? Thank you

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Reply:
click the Enter key once, KeyEvent.ACTION_DOWN and KeyEvent.ACTION_UP are triggered View.OnKeyListener (), so Toast display twice. You can put

 if (arg1 == KeyEvent.KEYCODE_ENTER) 

changed

 if (arg1 == KeyEvent.KEYCODE_ENTER && arg2.getAction () == KeyEvent.ACTION_DOWN) 

or

 if (arg1 == KeyEvent.KEYCODE_ENTER && arg2.getAction () == KeyEvent.ACTION_UP) < / pre> This will only show Toast at press ENTER or ENTER key release time. 
You can also be changed according to need, when pressed and released, Toast display different strings. 
  Reply:  
 if (arg1 == KeyEvent.KEYCODE_ENTER && arg2.getAction () == KeyEvent.ACTION_UP) 
 
Effective, thank you ah 
No. QQ how much you add you look.
  Reply:  
Results posted!!