android thread

Since the handler and the activity is run in the same thread, running in Thread () method Thread.sleep (5000), Why Thread the System.out.println without first implemented, but the first implementation of Activity in System.out . println ();

 package cc.handler2; 

import android.os.Bundle; 
import android.os.Handler; 
import android.app.Activity; 
import android.util.Log; 
import android.view.Menu; 

public class MainActivity extends Activity {

private Handler handler = new Handler (); 
@ Override 
protected void onCreate (Bundle savedInstanceState) {

super.onCreate (savedInstanceState); 
handler.post (thread); 
/ / Thread.start (); 
setContentView (R.layout.activity_main); 
System.out.println (. "Thread333 -" + Thread.currentThread () getId ()); 
System.out.println (. "Thread333 -" + Thread.currentThread () getName ()); 

} 

Thread thread = new Thread () 
{

public void run () 
{
System.out.println ("thread" + Thread.currentThread () getId ().); 
System.out.println ("thread" + Thread.currentThread () getName ().); 
try {
Thread.sleep (5000); 
} Catch (InterruptedException e) {
/ / TODO Auto-generated catch block 
e.printStackTrace (); 
} 
System.out.println ("thread" + Thread.currentThread () getId ().); 
System.out.println ("thread" + Thread.currentThread () getName ().); 


}; 
}; 
@ Override 
public boolean onCreateOptionsMenu (Menu menu) {
/ / Inflate the menu; this adds items to the action bar if it is present 
.getMenuInflater () inflate (R.menu.main, menu);. 
return true; 
} 

} 

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Reply:
The same question, I hope an expert answer