android webView how to set up the interception image size

Application webview Bianliaoge applet now ready to intercept Web Images
But using the Picture pic = webView.capturePicture (); each interception picture is the entire page, and I hope that the interception is a region of the screen, how to adjust the size of the interception area it?

 
cutButton.setOnClickListener (new View.OnClickListener () 
{
@ Override 
public void onClick (View v) 
{
Picture pic = webView.capturePicture (); 

int width = pic.getWidth (); 
int height = pic.getHeight (); 
if (width> 0 && height> 0) 
{
Bitmap bmp = Bitmap.createBitmap (width, height, Bitmap.Config.ARGB_8888); 
Canvas canvas = new Canvas (bmp); 
pic.draw (canvas); 
try 
{
String fileName = "sdcard /" + System.currentTimeMillis () + ". Png"; 
FileOutputStream fos = new FileOutputStream (fileName); 
if (fos! = null) 
{
bmp.compress (Bitmap.CompressFormat.PNG, 90, fos); 
fos.close (); 
} 
Toast.makeText (getApplicationContext (), "shot is successful, the file name is:" + fileName, Toast.LENGTH_SHORT) show (); 
.} 
catch (Exception e) 
{
e.printStackTrace (); 
} 
} 
} 
}); 

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Reply:

/ / Before the game development projects need to consider both adaptive screen then I wrote such a way to create the specified width and height of the picture, the desire to help the landlord.

 
/ ** 
* Create a new shrink or enlarge the image 
* 
* @ Param resources 
* @ Param resourcesID 
* @ Param scr_width 
* @ Param res_height 
* @ Return 
* / 
private Bitmap CreatMatrixBitmap (Bitmap bitMap, float scr_width, float res_height) {

int bitWidth = bitMap.getWidth (); 
int bitHeight = bitMap.getHeight (); 
float scaleWidth = scr_width / (float) bitWidth; 
float scaleHeight = res_height / (float) bitHeight; 
Matrix matrix = new Matrix (); 
matrix.postScale (scaleWidth, scaleHeight); 
bitMap = Bitmap.createBitmap (bitMap, 0, 0, bitWidth, bitHeight, matrix, true); 
return bitMap; 
} 

Reply:
The method capturePicture WebView () itself is copy Content currently displayed, then getWidth, getHeight method to get the width, height, and then createBitmap there is an error. . .

Get the current view of the starting position, width, height, width and height should be the current cell phone fishes ~ ~
Reply:
view.setDrawingCacheEnabled (true);
view.getDrawingCache ();
Interception on the current screen area
Reply:
It's very simple ah ..
Bitmap bmp = Bitmap.createBitmap (width, height, Bitmap.Config.ARGB_8888);
The width and height settings as you want does not have to
For example
Bitmap bmp = Bitmap.createBitmap (400, 200, Bitmap.Config.ARGB_8888);

Reply:
view.setDrawingCacheEnabled (true);
view.getDrawingCache ();

This method is to get a screenshot of the entire WebView (Content fewer words). If the content is high, pictures can not be generated.
Reply:

references, 4th Floor java312619570 reply:

It's very simple ah ..
Bitmap bmp = Bitmap.createBitmap (width, height, Bitmap.Config.ARGB_8888);
The width and height settings as you want does not have to
For example
Bitmap bmp = Bitmap.createBitmap (400, 200, Bitmap.Config.ARGB_8888);

This approach is taken in the first half of the image, instead of the current display. How should the currently displayed to take it?
Reply:
If you remove the outer layer of the listening event, let the program run directly intercept the contents of WebView, why complain. . . Show: get width, height is 0. . .
Request advice. . . .
Reply:
Many webview content, after the interception of 5000 pixels, the picture is very vague, a word not see country?