android4.0 sub-thread socket problem

android4.0 after the main UI thread can not be used in socket, the use of socket is a problem in the sub-thread. You can establish a connection, while (true) the contents are not implemented, do not know why ah


protected void onCreate (Bundle savedInstanceState) {
super.onCreate (savedInstanceState);
setContentView (R.layout.activity_main);
Intent intent = new Intent ();
intent.setClass (MainActivity.this, UsbDongleService.class);
bindService (intent, connection, Context.BIND_AUTO_CREATE);
edt = (EditText) findViewById (R.id.editText1);

Thread th = new Thread (new Runnable () {
@ Override
public void run () {
/ / TODO Auto-generated method stub
try {
socket = new Socket ("192.168.1.55", 4800);
in = new BufferedReader (new InputStreamReader (socket.getInputStream ()));
out = new PrintWriter (new BufferedWriter (new OutputStreamWriter (socket.getOutputStream ())), true);
} Catch (UnknownHostException e1) {
/ / TODO Auto-generated catch block
e1.printStackTrace ();
} Catch (IOException e1) {
/ / TODO Auto-generated catch block
e1.printStackTrace ();
}
while (true) {
Log.d ("socket", "1");
/ / Out.print (tv.getText ());
if (socket.isConnected ()) {
if (! socket.isInputShutdown ()) {
try {
if ((recMSG = in.readLine ())! = null) {
/ / Edt.setText ("\ n");
Log.d ("socket", in.readLine ());
socketHandler.sendMessage (socketHandler.obtainMessage ());
}
} Catch (IOException e) {
/ / TODO Auto-generated catch block
e.printStackTrace ();
if (servicedata) {
Log.d ("socket", "output");
servicedata = false;
out.println (tv.getText ());
}
}
}
}
}
}
});
th.start ();
}<-! Main posts under Banner (D4) -><-! Posts under the main text (D5) ->
Reply:
Did not see what the problem. . .
socketHandler.sendMessage (socketHandler.obtainMessage ());
obtainMessage To parameters?
Reply:
if ((recMSG = in.readLine ())! = null) {

}
Is not this place does not move? If the server does not send the data would not move.
Or you need to send data to the server.
Reply:

reference to the second floor birdsaction reply:

if (! (recMSG = in.readLine ()) = null) {

}
Is not this place does not move? If the server does not send the data would not move.
Or you need to send data to the server.

Yes, stop here, but the here readLine () after this one commented, app would force close together, causing the error should be
out.println (tv.getText ()); This one, this one does not know why the wrong
Reply:
The problem is resolved, it should be tv.getText () problem here
Reply:
Sub-thread want to update UI, you can use handler to do.
Reply:

references, 5th Floor tantahe reply:

child thread want to update UI, you can use the handler to do.

Yes, it is doing
Reply:
Asynchronous can also update the UI